(8x+1)(3x^2-20x-7)=0

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Solution for (8x+1)(3x^2-20x-7)=0 equation: 


Simplifying
(8x + 1)(3x2 + -20x + -7) = 0

Reorder the terms:
(1 + 8x)(3x2 + -20x + -7) = 0

Reorder the terms:
(1 + 8x)(-7 + -20x + 3x2) = 0

Multiply (1 + 8x) * (-7 + -20x + 3x2)
(1(-7 + -20x + 3x2) + 8x * (-7 + -20x + 3x2)) = 0
((-7 * 1 + -20x * 1 + 3x2 * 1) + 8x * (-7 + -20x + 3x2)) = 0
((-7 + -20x + 3x2) + 8x * (-7 + -20x + 3x2)) = 0
(-7 + -20x + 3x2 + (-7 * 8x + -20x * 8x + 3x2 * 8x)) = 0
(-7 + -20x + 3x2 + (-56x + -160x2 + 24x3)) = 0

Reorder the terms:
(-7 + -20x + -56x + 3x2 + -160x2 + 24x3) = 0

Combine like terms: -20x + -56x = -76x
(-7 + -76x + 3x2 + -160x2 + 24x3) = 0

Combine like terms: 3x2 + -160x2 = -157x2
(-7 + -76x + -157x2 + 24x3) = 0

Solving
-7 + -76x + -157x2 + 24x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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